
Conduct ttests to compare the mean of BMI for men vs women and to compare the mean of SBP for men vs women.
Group Statistics 

SEX 
N 
Mean 
Std. Deviation 
Std. Error Mean 

SBP 
Male 
539 
138.21 
20.854 
.898 
Female 
641 
139.06 
20.945 
.827 

BMI 
Male 
539 
26.7078 
3.37892 
.14554 
Female 
641 
25.8261 
4.07403 
.16091 
Independent Samples Test 

Levene`s Test for Equality of Variances 
ttest for Equality of Means 

F 
Sig. 
t 
df 
Sig. (2tailed) 
Mean Difference 
Std. Error Difference 
95% Confidence Interval of the Difference 

Lower 
Upper 

SBP 
Equal variances assumed 
.000 
.997 
.693 
1178 
.489 
.846 
1.222 
3.243 
1.551 

Equal variances not assumed 
.693 
1145.156 
.488 
.846 
1.221 
3.242 
1.550 

BMI 
Equal variances assumed 
14.218 
.000 
3.999 
1178 
.000 
.88174 
.22047 
.44918 
1.31429 

Equal variances not assumed 
4.064 
1177.784 
.000 
.88174 
.21697 
.45605 
1.30743 
Thesignificant pvalue are SBP= .997 and BMI=.000 with a 5% level ofsignificance. The mean between men vs women can be concluded to haveno difference.

The estimated coefficients for the linear regression pvalue= .000
Value= .213Estimated Residual Standard Deviation=3.70903the 95% CI for SBP for people with BMI of 25 is 130.039to 147.301the interval Coefficient is 20.855theslope coefficient is .039
C) Conduct a ttest to compare the mean of ADJSBP for men vs women,and interpret and compare your result to the ttest for SBP in (a).
tvaluesfor SBP when equal variances were assumed is .693 whereas tvaluesfor ADJSBP(below) .722
Independent Samples Test 

Levene`s Test for Equality of Variances 
ttest for Equality of Means 

F 
Sig. 
t 
df 
Sig. (2tailed) 
Mean Difference 
Std. Error Difference 
95% Confidence Interval of the Difference 

Lower 
Upper 

ADJSBP 
Equal variances assumed 
.000 
.989 
.722 
1178 
.470 
.880607353 
1.219771501 
3.273774438 
1.512559731 

Equal variances not assumed 
.722 
1144.889 
.470 
.880607353 
1.219388339 
3.273093847 
1.511879140 
Group Statistics 

SEX 
N 
Mean 
Std. Deviation 
Std. Error Mean 

ADJSBP 
Male 
539 
138.14489889 
20.830639455 
.897239159 
Female 
641 
139.02550624 
20.906423659 
.825754088 
2. A researcher was interested in comparing the success rates of twotherapies. She selected a sample of 500 people and randomly allocated250 to each therapy and evaluated the success rates. A summary of thedata are given below.
Group 
No 
Successful 
Therapy A 
250 
200 
Therapy B 
250 
180 
Successrate proportion for therapy A
200:50= 4:1(80%)
Thisimplies that 4 out of 1 or 80% of the people in therapy A would beundergo successful therapy
Success rate proportion for therapy B 180:70= 18:7(72%)this implies that 72% of the people in therapy B hadchance of undergoing successful therapy
Q 3
Summary of the interrater reliability data
Rater 2 

Absent 
Present 

Rater 1 
absent 
75 
35 
110 

present 
25 
65 
90 

100 
100 
200 

Proportion of parts for which the two raters were in agreement
%of exact agreement = Numberof observations agreed on TotalNumber of Observations
=75+65 200
P^=0.7
Witha confidence level of 95%, the confidence interval was calculated asfollows
P^=proportion = 0.05α = 10.95=.05( level of significance)
Zcritical value (from table) = 1.960 p±(z_{α}_{/2}√(p(1p)) n
Substitution0.71.960√ {(0.70.3)} < p < 0.7+1.960√{(0.70.3)} 200 200
0.70.032404<p<0.7+0.032404
0.6676<p<0.7324
Thewith a confidence level of 95 % the rate of agreement lies within66.76% and 73.24%.

Proportion of Parks for which the raters rated as having a play ground
Rater 1= 25/200= .125 (12.5%)
Rater 2 = 35/200 = .175(17.5%)
6