Question7.1: For each set of the sample outcomes, a 95% confidence will beconstructed for estimating µ, the population mean

X’= 5.2, S = 0.7,N = 157
Substitution
Therefore
< µ <
Substitution
<
Answer
5.1078 < µ< 5.2922

X’= 100, s =9, N= 620
Substitution
Therefore Confidence interval is denoted as
< µ <
Thus: answer
99.404937< µ < 100.595063

X’= 20, s =3, N= 220
Substitution
Therefore Confidence interval is denoted as
< µ <
Thus: answer
19.222252< µ < 20.333476
7.2.For each of the following sets of sample outcomes, the 99%confidence interval for estimating P_{u}denoted as (P’) Z critical value = 2.576 at CI 99% or α=.01

P’ = 0.14 N= 100
Substitution
Therefore answer
CI= 0.14±0.093685

P’= 0.37, N= 522
Substitution
Therefore answer
CI = .37 ± .054435

P’= .79, N= 121
Substitution
Therefore answer
CI= .79 ± .095384
Q.7.10 estimate of population value at 99% confidence level
Proportion=30% = 0.3
Confidencelevel= 99% z (Critical Value) = 2.576, N=324
Substitutionin (i).
Answer
CI=.3 ± .065582